a.b[i]is the same thing as
Here a is a structure and b is his member (b is an array or a pointer).
I read an article about precedence of c operators just now and it told me that the [ ] (brackets) operator is prior to the .(point), and the associativity of these two c operators is left-to-right :
 have the same precedence, and are evaluated from left-to-right. The expression
a.b[i] is the same as
a.b.c[i].d[j] is evaluated as: