# java - Wrong Decimal Representation of Hexadecimal Value

I have a small data set in HexaDecimal Representation -

byte[] bb = new byte[] { (byte)0x7D, (byte)0x44, (byte)0xCC };

To understand how the values are coming in Decimal Representation, I did the following -

``Log.i("DECIMAL VALUE of 7D>>", buf[i] + "");Log.i("DECIMAL VALUE of 44>>", buf[i+1] + "");Log.i("DECIMAL VALUE of CC>>", buf[i+2] + "");``

And what it printed was -

``DECIMAL VALUE of 7D>> 125DECIMAL VALUE of 44>> 68DECIMAL VALUE of CC>> -52``

Looking into the site -

http://hextodecimal.com/index.php?hex=CC

The Decimal Representation of byte `CC` is `204`.

In my application I am getting `Index Out Of Bounds Exception` just because index at `-52` doesn't exist in the bounds.

So how is this byte coming negative and what is the clear solution.

Bytes in Java are signed i.e. they range from -128 to 127. If you want to represent the number 204, use an `int`.

``````int[] bb = new int[] { 0x7D, 0x44, 0xCC };
``````

If you really want to store the data as bytes, you can convert it to unsigned where you use it to index in an array.

``````yourArray[bb && 0xFF]
``````

See the following question: How to Convert Int to Unsigned Byte and Back