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Can Ruby operators be aliased?

问题描述:

I'm interested in how one would go in getting this to work :

me = "this is a string"

class << me

alias :old<< :<<

def <<(text)

old<<(text)

puts "appended #{text}"

end

end

I'd like that when something gets appended to the me variable, the object will use the redefined method.

If I try to run this, I get syntax error, unexpected ':', expecting kEND at :<<.

网友答案:

:old<< looks like ":old <<". Try just :old, or if you really want, :"old<<" (but have fun calling it through that name).

网友答案:

Only certain characters are allowed in symbol literals. You are looking for:

alias :"old<<" :"<<"
网友答案:

As others have already explained, the problem is simply that old<< is not a legal Ruby identifier. You can, with tricks, create a method with that name, but you can't call it in the normal ways, and it certainly won't be recognized as an operator.

However, all the answers so far, while they have certainly answered your question, have completely ignored the underlying problem: that method shouldn't even have a name in the first place! And if it doesn't have a name, then the problem of the name being illegal simply doesn't even arise.

#!/usr/bin/env ruby

require 'test/unit'
require 'stringio'
class TestOperatorDecorator < Test::Unit::TestCase
  def setup; @old_stdout, $> = $>, (@fake_stdout = StringIO.new) end
  def teardown; $> = @old_stdout end

  def test_that_me_dot_append_writes_to_stdio
    me = 'this is a string'
    class << me
      old_method = instance_method :<<

      define_method :<< do |text|
        old_method.bind(self).(text)
        puts "appended #{text}"
      end
    end

    me << 'Test'

    assert_equal "appended Test\n", @fake_stdout.string
  end
end

In this case, the method never gets named, which not only means that we don't have to invent a name for it, it also means that it doesn't pollute the namespace.

网友答案:

The problem is with :old<<. It gets interpreted as :old <<, i.e. a symbol :old followed by the << operator, so it is a syntax error. Maybe you can try :"old<<"?

网友答案:

While I agree with thenduks and ephemient, You can alias the operator that way then use send to call it, you can also still use class inheritance. e.g.:

me = "is a string"

class << me
  def <<(text)
    super
    puts "appended #{text}"
  end
end

me << " bob"
puts me #=> is a string appended bob
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