Java经典实例:找到匹配的文本

来源:转载

import java.util.regex.Matcher;

import java.util.regex.Pattern;

/**

* Created by Frank

*/

public class REMatch {

public static void main(String[] args) {

String patt = "Q[^u]\\d+\\.";

Pattern r = Pattern.compile(patt);

String line = "Order QT300. Now! QT400.";

Matcher m = r.matcher(line);

int i = 0;

while (m.find()) {

// group(0)或group()将会返回整个匹配的字符串(完全匹配);group(i)则会返回与分组i匹配的字符

// 这个例子只有一个分组

System.out.println(patt + " matches \"" + m.group(0) + "\" in \"" + line + "\"");

System.out.println("start:" + m.start() + " end:" + m.end());

}

}

}

输出:

Q[^u]\d+\. matches "QT300." in "Order QT300. Now! QT400."

start:6 end:12

Q[^u]\d+\. matches "QT400." in "Order QT300. Now! QT400."

start:18 end:24

 

import java.util.regex.Matcher;

import java.util.regex.Pattern;

/**

* Created by Frank

*/

public class REMatchTwoFields {

public static void main(String[] args) {

String inputLine = "Adams,John Quincy";

Pattern r = Pattern.compile("(.*),(.*)");

Matcher m = r.matcher(inputLine);

if (!m.matches()) {

throw new IllegalArgumentException("Bad Input");

}

// 分组0得到的是整个原字符串

for (int i = 0; i < m.groupCount() + 1; i++) {

System.out.println("分组" + i + ":" + m.group(i));

}

}

}

输出:

分组0:Adams,John Quincy

分组1:Adams

分组2:John Quincy

 

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